如何拆分带重复元素的集合
对于包含重复元素的集合，需要拆分成多个不带重复元素的小集合。以下是如何使用 python 来解决此问题：
datas = [29, 36, 37, 37, 39, 39, 955, 955, 955, 961, 961, 962, 962]
elementcounts = {}
maxcount = 0
for data in datas:
if data in elementcounts:
count = elementcounts[data]
else:
count = 0
elementcounts[data] = count + 1
if count + 1 > maxcount:
maxcount = count + 1
sets = []
for i in range(maxcount):
sets.append(set())
for key in elementcounts.keys():
count = elementcounts[key]
for i in range(count):
sets[i].add(key)
print(sets)此代码会创建多个集合，其中每个集合包含不重复的元素。在给定的示例中，将输出以下集合：
[set([29, 36, 37, 39, 955, 961, 962]), set([37, 39, 955, 961, 962]), set([955])]
