php post提交。问题
假如post提交：
user=name1&password1=123456&password2=123456
这样的连接
我想name｛num｝
num｛｝=1，2，3，4，5，6等等
这里的变量怎么写？
源码如下：
- PHP code
<!--Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--><?php$domain = "www.xxxx.xxx";$port = 80;$uri = "/reg.php?cont=store_user";$refe = "http://www.xxxx.xxx/reg.php";$num=1;$data ="lang=Chinese&username=like{$num}&password1=123456&password2=123456&mobile=&email=&srvid=1&textarea=%E6%8F%90%E7%A4%BA%EF%BC%9A%E8%AF%B7%E4%BB%94%E7%BB%86%E9%98%85%E8%AF%BB%E4%BB%A5%E4%B8%8B%E6%9D%A1%E6%AC%BE%EF%BC%8C%E5%86%8D%E6%B3%A8%E5%86%8C%E5%B8%90%E5%8F%B7%E3%80%82%E4%BD%BF%E7%94%A8%E6%9C%AC%E7%BD%91%E7%AB%99%E8%A1%A8%E7%A4%BA%E6%82%A8%E5%90%8C%E6%84%8F%E9%81%B5%E5%AE%88%E8%BF%99%E4%BA%9B%E6%9D%A1%E6%AC%BE%E5%92%8C%E6%9D%A1%E4%BB%B6%E3%80%82%E5%A6%82%E6%9E%9C%E6%82%A8%E4%B8%8D%E6%8E%A5%E5%8F%97%E8%BF%99%E4%BA%9B%E6%9D%A1%E6%AC%BE%EF%BC%88%E2%80%9C%E6%9D%A1%E6%AC%BE%E2%80%9D%EF%BC%89%EF%BC%8C%E8%AF%B7%E5%8B%BF%E6%B3%A8%E5%86%8C%E3%80%82&acceptterms=1&adduser=%E5%88%9B%E5%BB%BA%E8%B4%A6%E6%88%B7";$protocolstr = "POST {$uri} HTTP/1.1\nAccept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, application/x-shockwave-flash, */*\nReferer: {$refe}\r\nAccept-Language: zh-cn\nContent-Type:application/x-www-form-urlencoded\nAccept-Encoding: gzip, deflate\nUser-Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 2.0.50727; 360SE)\nHost: {$domain}\nContent-Length: 702\nConnection: Keep-Alive\nCache-Control: no-cache\nCookie: login_user=aabbcc02; PHPSESSID=hs23i9tguang96k7del3oafc64; lzstat_uv=2113815751356026816|2652038; lzstat_ss=2265145365_0_1335089150_2652038\n\n{$data}";for ($i=1; $i<100;$i++){ for(;$num<10;$num++)$sock = fsockopen($domain, $port, $errno, $errstr, 30);if (!$sock) die("$errstr ($errno)\n"); fputs($sock, $protocolstr);$headers = ""; while ($str = trim(fgets($sock, 4096))) $headers .= "$str\n"; $body = ""; while (!feof($sock)) $body .= fgets($sock, 4096); fclose($sock); }echo "<h2>Response header:</h2>\n"; echo $headers; echo "\n"; echo "<h2>Response body:</h2>\n"; echo $body;?> ------解决方案--------------------
3楼被删？？
写个文件初始内容为1，post之前读取文件取出数值$num，得到name.$num，post之后把$num加1再写入这个文件
------解决方案--------------------
//post之前
$filenum="num.txt";
$fnum=fopen($filenum,"r");
if(!$num=fgetc($fnum))
{$num=0;}
.......你的操作
//post之后
$filenum="num.txt";
$fnum=fopen($filenum,"r");
if(!$num=fgetc($fnum))
{$num=0;}
else
{$num=intval($num)++;
fclose($fnum);
$fnumw=fopen($filenum,"w");
fwrite(fnumw,strval($num));
fclose($filenum);
}
?>
