为什么PHP不能接收。。
$.ajax({<br>
type: "POST",<br>
url: "index.php",<br>
data: "location=img_png_src",<br>
success: function(msg){<br>
alert( "Data Saved: " + msg );<br>
}<br>
});<br>
<?php echo $_POST["location"]; ?>
PHP接受不了 报错了 Notice: Undefined index: location in C:\wamp\www\makebanner\index.php on line 45
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------解决方案--------------------
------解决方案--------------------
<?php<br>
if($_SERVER['REQUEST_METHOD'] == "POST") {<br>
print_r($_POST);<br>
exit();<br>
}<br>
?><br>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.3/jquery.min.js"></script><br>
<script><br>
$(function() {<br>
$.ajax({<br>
type: "POST",<br>
// url: "index.php",<br>
data: "location=img_png_src",<br>
success: function(msg){<br>
alert( "Data Saved: " + msg );<br>
}<br>
});<br>
});<br>
</script><br>
