数组拆分处理（整数时的处理）
已知数组a：
array (<br> 0 => <br> array (<br> 'po_num' => '20131227-000008102',<br> 'plant' => 'JQSP',<br> 'get_date' => '2013-12-27',<br> 'cust_no' => '12654172',<br> 'total' => '225',<br> 'snp' => '15',<br> 'mount' => '15',<br> 'lp_no' => 'P000000D',<br> ),<br> )
处理程序如下：
<br>
$t = 225;<br>
$k = 0;<br>
<br>
foreach($a as $v) {<br>
$t1 = $v['total'];<br>
$v['total'] = $t1 % $t;<br>
$res[$k][] = $v;<br>
$t1 -= $v['total'];<br>
while($t1 >= $t) {<br>
$v['total'] = $t;<br>
$t1 -= $t;<br>
$res[++$k][] = $v;<br>
}<br>
}<br>
$res = array_reverse($res);<br>
print_r($res);<br>
得到的结果：
Array<br> (<br> [0] => Array<br> (<br> [0] => Array<br> (<br> [po_num] => 20131227-000008102<br> [plant] => JQSP<br> [get_date] => 2013-12-27<br> [cust_no] => 12654172<br> [total] => 225<br> [snp] => 15<br> [mount] => 15<br> [lp_no] => P000000D<br> )<br> <br> )<br> <br> [1] => Array<br> (<br> [0] => Array<br> (<br> [po_num] => 20131227-000008102<br> [plant] => JQSP<br> [get_date] => 2013-12-27<br> [cust_no] => 12654172<br> [total] => 0 //产生了为0的项<br> [snp] => 15<br> [mount] => 15<br> [lp_no] => P000000D<br> )<br> <br> )<br> <br> )
既然是整除，那么结果应该只有一项，如何修改代码让其只有非0项生成？
