显示数据库中blob类型的图片，我图片显示不出来
showimage.php
<?php <br>
include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/utilityfunction/SqlHelp.class.php';<br>
include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/Comm.class.php';<br>
<br>
$SqlHelper = new SqlHelp ( 'read', 'qztoa' );<br>
$sql = "select * from qzt_image";<br>
$query = $SqlHelper->query($sql );<br>
$query_num = $SqlHelper->num_rows ($query );<br>
<br>
$rows = array (); <br>
$retarr = array (); <br>
$query =$SqlHelper->query ( $sql );<br>
if($query)<br>
{<br>
$arr_teainfo2 = array ();<br>
while ( $arr_teainfo = $SqlHelper->fetch_assoc($query) ) {<br>
$arr_teainfo2 [] = $arr_teainfo;<br>
$Id=$arr_teainfo["Id"];<br>
echo $arr_teainfo["Id"];<br>
echo "<IMG SRC=\"Second.php3?Id=$Id\">"; <br>
<br>
}<br>
}<br>
<br>
<br>
<br>
?> <br>
Second.php3
<?php <br>
include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/utilityfunction/SqlHelp.class.php';<br>
include_once dirname(dirname (dirname ( __FILE__ ))). '/yeqztsys1.0/Comm.class.php';<br>
<br>
$SqlHelper = new SqlHelp ( 'read', 'qztoa' );<br>
$sql = "select * from qzt_image where Id=10";<br>
$query = $SqlHelper->query($sql );<br>
$query_num = $SqlHelper->num_rows ($query );<br>
<br>
$rows = array (); <br>
$retarr = array (); <br>
$query =$SqlHelper->query ( $sql );<br>
if($query)<br>
{<br>
$arr_teainfo2 = array ();<br>
while ( $arr_teainfo = $SqlHelper->fetch_assoc($query) ) {<br>
$arr_teainfo2 [] = $arr_teainfo;<br>
$Id=$arr_teainfo["Id"];<br>
$imagetype=$arr_teainfo["imagetype"];<br>
//echo $arr_teainfo["images"];<br>
//Header( "Content-type: $imagetype"); <br>
header('Content-type: $imagetype');<br>
echo $arr_teainfo["images"];<br>
<br>
}<br>
}<br>
<br>
?> <br>
请问我哪里有问题？PHP新人，不知道哪里错了
PHP
