PHP跳转菜单读取值问题
我把
- PHP code
<html>
<head>
</head>
<body>
<?php
if(isset($_POST['abc']))
{
var_dump($_POST['abc']);
var_dump($_POST);
}else
{
echo ('
<form action="'.$_SERVER['PHP_SELF'].'" method="post">
<select name="abc">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
<input type="submit" value="submit"/>
</form>');
}
?>
</body>
</html>
<br><font color="#e78608">------解决方案--------------------</font><br>你是怎么写的代码？
<br><font color="#e78608">------解决方案--------------------</font><br>用js就能获取
<br><font color="#e78608">------解决方案--------------------</font><br>两次foreach <div class="clear">
</div>
