日历问题
2012年02月
星期一 星期二 星期三 星期四 星期五 星期六 星期日
6 7 8 9 10 11 12
13 14 15 16 17 18 19
帮忙写写。谢谢
------解决方案--------------------
- PHP code
year=isset($_GET['year']) ? $_GET['year'] : date("Y");
$this->month=isset($_GET['month']) ? $_GET['month'] : date("m");
$this->day_week=date("w", mktime(0, 0, 0, $this->month, 1, $this->year));
}
private function xianDate(){
echo "";
echo ""." ";
echo ""."";
echo "
".$this->year."年".$this->month."月 ";
echo "".">>"." ";
echo "".">>>"." ";
echo " ";
}
private function weeks(){
$weeks=array("日", "一", "二", "三", "四", "五", "六");
echo "";
foreach($weeks as $value){
echo "".$value." ";
}
echo " ";
}
private function days(){
echo "";
for($i=0; $iday_week; $i++){
echo " ";
}
for($j=1; $j month, 1, $this->year)); $j++){
$i++;
if($j == date("d")){
echo "".$j." ";
}else{
echo "".$j." ";
}
if($i%7 == 0){
echo " ";
}
}
while($i%7 != 0){
echo " ";
$i++;
}
}
private function nextyear($year, $month){
if($year == 1970){
$year=1970;
}else{
$year--;
}
return "?year=".$year."&month=".$month;
}
private function afteryear($year, $month){
if($year == 2038){
$year=2038;
}else{
$year++;
}
return "?year=".$year."&month=".$month;
}
private function nextmonth($month, $year){
if($month == 1){
$year--;
$month=12;
}else{
$month--;
}
return "?year=".$year."&month=".$month;
}
private function aftermonth($month, $year){
if($month == 12){
$year++;
$month=1;
}else{
$month++;
}
return "?year=".$year."&month=".$month;
}
public function out(){
echo "
