详细介绍c#时间戳和js时间戳互转方法的代码分享

下面小编就为大家带来一篇js时间戳和c#时间戳互转方法(推荐)。小编觉得挺不错的，现在就分享给大家，也给大家做个参考。一起跟随小编过来看看吧

实例如下：

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using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using Newtonsoft.Json;

namespace TestWeb
{
  public partial class ajax : System.Web.UI.Page
  {
    protected void Page_Load(object sender, EventArgs e)
    {
      if (!IsPostBack)
      {
        //TestAjax()
      }
    }

    public void TestAjax()
    {
      var phone = Request.Form["phone"];
      var authcode = Request.Form["authcode"];
      var pt = Request.Form["pt"]; //js时间戳 new Date().getTime() eg: 1429503106452

      string outputmsg = string.Empty;

      if (phone != null && authcode != null && pt != null)
      {
        DateTime dtStart = TimeZone.CurrentTimeZone.ToLocalTime(new DateTime(1970, 1, 1));
        //说明下，时间格式为13位后面补加4个"0"，如果时间格式为10位则后面补加7个"0"
        long lTime = long.Parse(pt + (pt.Length == 13 ? "0000" : "0000000"));
        TimeSpan toNow = new TimeSpan(lTime);
        DateTime dtResult = dtStart.Add(toNow); //得到转换后的时间

        string str = dtResult.ToString();
        outputmsg = OutMsg(new ResponseInfo { success = true, tag = 100, msg = "成功" });
      }

      Response.Write(outputmsg);
    }

    public long GetCurrentTicksForJs()
    {
      System.DateTime startTime = TimeZone.CurrentTimeZone.ToLocalTime(new System.DateTime(1970, 1, 1, 0, 0, 0, 0));
      DateTime dtResult = DateTime.Now;//获取时间     
      long t = (dtResult.Ticks - startTime.Ticks) / 10000;//除10000调整为13位
      return t;
    }

    public string OutMsg(object obj)
    {
      return JsonConvert.SerializeObject(obj, Newtonsoft.Json.Formatting.Indented);
    }

    public class ResponseInfo
    {
      public bool success { get; set; }
      public int tag { get; set; }
      public string msg { get; set; }
    }

    //...

  }
}<%@ Page Language="C#" AutoEventWireup="true" CodeBehind="ajax.aspx.cs" Inherits="TestWeb.ajax" %>


var date = new Date(1459481266695);
Y = date.getFullYear() + '-';
M = (date.getMonth()+1 < 10 ? '0'+(date.getMonth()+1) : date.getMonth()+1) + '-';
D = date.getDate() + ' ';
h = date.getHours() + ':';
m = date.getMinutes() + ':';
s = date.getSeconds(); 
console.log(Y+M+D+h+m+s); 
VM307:9 2016-04-1 11:27:46