Ajax如何传输Json和xml数据

这篇文章主要为大家详细介绍了ajax如何传输json和xml数据,具有一定的参考学习ajax的价值，对ajax如何传输json和xml数据感兴趣的或不熟悉的小伙伴们可以参考一下

ajax传输xml数据：只要把数据封装成xml格式就可以实现传输，前台js用responseXML接收xml参数，后台读取用流和dom4j来解析

前台页面

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>












 Name:
 
 
 Age:
 
 

 
 

 
 

后台页面

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>












 Name:
 
 
 Age:
 
 

 
 

 
 

--------------------------------------------------------------------------------

Ajax传输Json数据的要点利用Apache或者阿里巴巴的JSONArray类进行传输
前台代码

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>









 
 

 
 

JsonServlet1.java

package cn.hncu.servlet;

import java.io.IOException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.List;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import cn.hncu.domain.User;

public class JsonServlet1 extends HttpServlet {

 public void doGet(HttpServletRequest request, HttpServletResponse response)
   throws ServletException, IOException {
  doPost(request, response);
 }


 public void doPost(HttpServletRequest request, HttpServletResponse response)
   throws ServletException, IOException {
  //调用后台service.dao.query()，到数据库当中把信息读取出来
  //为简化知识点的理解，此处后台部分的功能直接模拟
  response.setContentType("text/html;charset=utf-8");
  PrintWriter out = response.getWriter();
  List users = new ArrayList();
  users.add(new User("A001","Jack",20));
  users.add(new User("A002","Rose",22));
  users.add(new User("B001","张三",20));
  users.add(new User("B002","李四",30));
  String json="";
  //用java封装出json格式的字符串：[{name:"Jack",age:25}, {...}, {...} ]
  for(User u:users){
   if(json.equals("")){
    json="{name:\""+u.getName()+"\",id:\""+u.getId()+"\",age:"+u.getAge()+"}";
   }else{
    json = json +",{ name:\""+u.getName()+"\",id:\""+u.getId()+"\",age:"+u.getAge()+"}" ;
   }
  }
  json="["+json+"]";
  out.print(json);
 }

}

JsonServlet2.java

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package cn.hncu.servlet;

import java.io.IOException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import cn.hncu.domain.User;

import net.sf.json.JSONArray;
import net.sf.json.JSONObject;

public class JsonServlet2 extends HttpServlet {

 public void doPost(HttpServletRequest request, HttpServletResponse response)
   throws ServletException, IOException {

  response.setContentType("text/html;charset=utf-8");
  PrintWriter out = response.getWriter();
  List users = new ArrayList();
  users.add(new User("A001","Jack",20));
  users.add(new User("A002","Rose",22));
  users.add(new User("B001","张三",20));
  users.add(new User("B002","李四",30));
  String strJson=com.alibaba.fastjson.JSONArray.toJSONString(users);
  System.out.println(strJson);
  //用fastjson工具(只有一个jar包)帮我们把list转换成json串
  Map map = new HashMap();
  map.put("addr", "湖南");
  map.put("height", "170");
  map.put("marry", "no");
  map.put("user", new User("A003","小李",25));
  String strMap=com.alibaba.fastjson.JSONArray.toJSONString(map);

  out.print(strMap.toString());
 }

}

JsonServlet3.java

package cn.hncu.servlet;

import java.io.IOException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import net.sf.json.JSONArray;
import net.sf.json.JSONObject;
import cn.hncu.domain.User;

public class JsonServlet3 extends HttpServlet {

 public void doPost(HttpServletRequest request, HttpServletResponse response)
   throws ServletException, IOException {

  response.setContentType("text/html;charset=utf-8");
  PrintWriter out = response.getWriter();
  List users = new ArrayList();
  users.add(new User("A001","Jack",20));
  users.add(new User("A002","Rose",22));
  users.add(new User("B001","张三",20));
  users.add(new User("B002","李四",30));
  //用fastjson工具(只有一个jar包)帮我们把list转换成json串
  JSONArray json=JSONArray.fromObject(users);
  String strJson=json.toString();
  System.out.println(strJson);

  Map map = new HashMap();
  map.put("addr", "湖南");
  map.put("height", "170");
  map.put("marry", "no");
  map.put("user", new User("A003","小李",25));
  JSONObject obj = JSONObject.fromObject(map);
  System.out.println(obj.toString());

  out.print(obj.toString());
 }

}

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持PHP中文网。

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