参考下面的算法，编写C程序以显示X形状的数字。
算法
Step 1: Start Step 2: Declare variables Step 3: Read number of rows Step 4: for loop satisfies<ul class="list"><li>if(i==j || i+j==rows-1)<ul class="list"><li>print i+1</li></ul></li><li>Print " "</li></ul>Step 5: Print new line Step 6: Stop
The logic to print numbers in X pattern is as follows −
for(i=0;i<rows;i++){
for(j=0;j<rows;j++){
if(i==j || i+j==rows-1){
printf("%d",i+1);
}else{
printf(" ");
}
}
printf("</p><p>");
}Program
Following is the C program to display the numbers in X pattern −
#include<stdio.h>
main(){
int i,j,rows;
printf("Enter number of rows:</p><p>");
scanf("%d",&rows);
for(i=0;i<rows;i++){
for(j=0;j<rows;j++){
if(i==j || i+j==rows-1){
printf("%d",i+1);
}else{
printf(" ");
}
}
printf("</p><p>");
}
}输出
当上述程序被执行时，它产生以下结果 −
Enter number of rows:10
1 1
2 2
3 3
4 4
55
66
7 7
8 8
9 9
10 10 
