每年 5 月 7 日，全球组织都会提醒用户强密码的重要性。根据科技巨头谷歌的说法；
他们的终端用户中有24%将单词"password"或"Qwerty"作为他们的账户密码。
虽然，只有34%的用户经常更改他们的账户密码。
在当今这个技术先进的世界中，每次登录尝试都有可能遭受网络犯罪攻击。但现在许多人仍然在其专业和个人帐户中使用弱密码。
在这里，我们将讨论和检查所创建的密码是非常弱、弱、中等、强还是非常强。为此，我们将按照算法的要求来检查密码的创建标准。在今天的文章中，我们将学习如何使用C++代码创建一个强密码建议器。
如何创建强密码 - 算法
这是一个强密码的通用算法。它帮助开发者在C++环境中开发密码建议系统，并找到密码的特定标准。
步骤 1 − 开始
步骤 2 - 理想密码的长度应至少为八个字符。
步骤 3 − 必须包含至少一个数字字符。
第四步 - 至少应该有一个小写字母。[示例：a，b，c.....，z]
第五步 - 至少应该有一个大写字母。[示例：A，B，C......，Z]
步骤 6 − 它应该包含至少一个特殊字符。[示例：!@#$ %^&*()-+]
第 7 步 - 结束
创建一个强密码建议者 - 语法
switch (k) {
case 1:
if ((count_alphabet == 7) && (count_number == 0 || count_ALPHABET == 0 || count_ALPHABET == 7 || count_s_symbol == 0))
break;
key = getKey();
password = password + alphabet[key];
count_alphabet++;
count++;
break;
case 2:
if ((count_ALPHABET == 7) && (count_number == 0 || count_alphabet == 0 || count_alphabet == 5 || count_s_symbol == 0))
break;
key = getKey();
password = password + ALPHABET[key];
count_ALPHABET++;
count++;
break;
case 3:
if ((count_number == 7) && (count_alphabet == 0 || count_alphabet == 1 || count_ALPHABET == 3 || count_ALPHABET == 0 || count_s_symbol == 0))
break;
key = getKey();
key = key % 10;
password = password + number[key];
count_number++;
count++;
break;
case 4:
if ((count_s_symbol == 1) && (count_alphabet == 0 || count_alphabet == 1 || count_ALPHABET == 0 || count_ALPHABET == 1 || count_number == 0))
break;
key = getKey();
key = key % 6;
password = password + s_symbol[key];
count_s_symbol++;
count++;
break;
}
cout << "\n-----------------------------\n";
cout << " Enter The Password \n";
cout << "------------------------------\n\n";
cout << " " << password add here;
cout << "\n\n Press any key continue \n";
getchar();
}
在这个语法中，条件检查了一个理想密码的最低要求。我们将每个可能的条件分为四种情况，检查是否满足了字母、数字和特殊符号字符的要求，以及是否满足了最低要求。在处理过程中，如果还有其他字符剩下，那么它将会被忽略。
方法 - 创建一个强密码建议者
方法 1 - 创建强密码建议环境
方法 2 - 检查密码是强、弱还是中等
方法三 - 检查密码是否符合条件
创建一个强密码建议环境
在此 C++ 构建代码中，系统将检查输入数据（密码）的强度。它将扫描输入以查找理想密码的所有提到的标准。如果所有条件都匹配，那么它就是一个理想的密码。否则，输入中缺少任何字符，它将返回一些随机生成的密码。
Example 1
的中文翻译为：示例 1
#include <bits/stdc++.h>
using namespace std;
string add_more_char(string str, int need){
int pos = 0;
string low_case = "abcdefghijklmno";
for (int a = 0; a < need; a++) {
pos = rand() % str.length();
str.insert(pos, 1, low_case[rand() % 26]);
}
return str;
}
string suggester(int m, int o, int a, int d, string str) {
string num = "0123456789";
string low_case = "abcdefghijklmno";
string up_case = "ABCDEFGHIJKLMNO";
string spl_char = "@#$_()!*&%#+-=.`";
int pos = 0;
if (m == 0) {
pos = rand() % str.length();
str.insert(pos, 1, low_case[rand() % 26]);
}
if (o == 0) {
pos = rand() % str.length();
str.insert(pos, 1, up_case[rand() % 26]);
}
if (a == 0) {
pos = rand() % str.length();
str.insert(pos, 1, num[rand() % 10]);
}
if (d == 0) {
pos = rand() % str.length();
str.insert(pos, 1, spl_char[rand() % 7]);
}
return str;
}
void generate_password(int n, string p){
int l = 0, u = 0, d = 0, s = 0, need = 0;
string suggest;
for (int j = 0; j < n; j++) {
if (p[j] >= 97 && p[j] <= 122)
l = 1;
else if (p[j] >= 65 && p[j] <= 90)
u = 1;
else if (p[j] >= 48 && p[j] <= 57)
d = 1;
else
s = 1;
}
if ((l + u + d + s) == 4) {
cout << "Hurra! Your Passcode Is Strong, Go Ahead!" << endl;
return;
}
else
cout << "Suggested password As Per The Input. Pick One For You! " << endl;
for (int i = 0; i < 10; i++) {
suggest = suggester(l, u, d, s, p);
need = 8 - suggest.length();
if (need > 0)
suggest = add_more_char(suggest, need);
cout << suggest << endl;
}
}
int main(){
string input_string = "abonirudra@1607";
srand(time(NULL));
generate_password(input_string.length(), input_string);
return 0;
}
输出
Suggested password As Per The Input. Pick One For You! abonirudGra@1607 abConirudra@1607 abonirudra@1E607 abonirudra@16A07 abonirudra@160L7 abNonirudra@1607 aNbonirudra@1607 abonirDudra@1607 aboniruFdra@1607 abonirNudra@1607
检查密码强度是否强、弱或中等
根据上述算法和C++构建代码；编码字符串检查输入强度。当满足所有条件时，整个方法返回“Strong”作为输出。如果仅满足前三个步骤并且密码长度至少为八个字符，则它将返回“中等”。
Example 2
的中文翻译为：示例2
#include <bits/stdc++.h>
using namespace std;
void printStrongNess(string& input) {
int n = input.length();
bool hasLower = false, hasUpper = false;
bool hasDigit = false, specialChar = false;
string normalChars = "abcdefghijklmnopqrstu"
"vwxyzABCDEFGHIJKL023456789 ";
for (int i = 0; i < n; i++) {
if (islower(input[i]))
hasLower = true;
if (isupper(input[i]))
hasUpper = true;
if (isdigit(input[i]))
hasDigit = true;
size_t special = input.find_first_not_of(normalChars);
if (special != string::npos)
specialChar = true;
}
cout << "Strength of password:-";
if (hasLower && hasUpper && hasDigit &&
specialChar && (n >= 8))
cout << "Strong" << endl;
else if ((hasLower || hasUpper) &&
specialChar && (n >= 6))
cout << "Moderate" << endl;
else
cout << "Weak" << endl;
}
int main(){
string input = "Abonirudra@22052023";
printStrongNess(input);
return 0;
}
输出
Strength of password:-Strong
根据条件检查您的密码
在这段代码中，我们将对特定密码进行验证操作。以下是具体的步骤 -
接受用户的输入。
现在将检查用户输入的密码组合。
密码分为强、中、弱三种。
如果所有条件都为真，则它将是一个强密码。
其他情况下，中等或弱。
Example 3
的中文翻译为：示例 3
#include <bits/stdc++.h>
using namespace std;
void checkpassword(string& password) {
int n = password.length();
bool hasLower = false, hasUpper = false, hasDigit = false;
for (int i = 0; i < n; i++) {
if (islower(password[i]))
hasLower = true;
if (isupper(password[i]))
hasUpper = true;
if (isdigit(password[i]))
hasDigit = true;
}
cout << "Strength of password you have entered as per the input :-";
if ( hasUpper && hasDigit && hasLower && (n >= 6))
cout << "Strong" << endl;
else if ((hasLower || hasUpper) && hasDigit && (n >=6))
cout << "Moderate" << endl;
else
cout << "Weak" << endl;
}
int main() {
cout << "Welcome To The Password Tester! Let's Check Your Password. " << endl;
cout << "Let's consider the average length of an ideal strong password should be more than 6 character " << endl;
cout << "Please enter your desired password with :- " << endl;
cout << " * at least one upper case letter and lower case letter " << endl;
cout << " * and also need to have at least one digit " << endl; string password;
cout <<"Enter your monermoto password"<<endl;
getline(cin,password);
checkpassword(password);
return 0;
}
输出
Welcome To The Password Tester! Let's Check Your Password. Let's consider the average length of an ideal strong password should be more than 6 character Please enter your desired password with :- * at least one upper case letter and lower case letter * and also need to have at least one digit Enter your monermoto password Strength of password you have entered as per the input :-Weak
结论
从本文中，我们了解了如何使用 C++ 创建密码建议器环境，然后在该特定平台上如何使用一些标签（强、中等、弱）评估密码质量。
