强密码建议程序

每年 5 月 7 日，全球组织都会提醒用户强密码的重要性。根据科技巨头谷歌的说法；

• 他们的终端用户中有24%将单词"password"或"Qwerty"作为他们的账户密码。

• 虽然，只有34%的用户经常更改他们的账户密码。

在当今这个技术先进的世界中，每次登录尝试都有可能遭受网络犯罪攻击。但现在许多人仍然在其专业和个人帐户中使用弱密码。

在这里，我们将讨论和检查所创建的密码是非常弱、弱、中等、强还是非常强。为此，我们将按照算法的要求来检查密码的创建标准。在今天的文章中，我们将学习如何使用C++代码创建一个强密码建议器。

如何创建强密码 - 算法

这是一个强密码的通用算法。它帮助开发者在C++环境中开发密码建议系统，并找到密码的特定标准。

• 步骤 1 − 开始

• 步骤 2 - 理想密码的长度应至少为八个字符。

• 步骤 3 − 必须包含至少一个数字字符。

• 第四步 - 至少应该有一个小写字母。[示例：a，b，c.....，z]

• 第五步 - 至少应该有一个大写字母。[示例：A，B，C......，Z]

• 步骤 6 − 它应该包含至少一个特殊字符。[示例：!@#$ %^&*()-+]

• 第 7 步 - 结束

创建一个强密码建议者 - 语法

switch (k) {
   case 1:
      if ((count_alphabet == 7) && (count_number == 0 || count_ALPHABET == 0 || count_ALPHABET == 7 || count_s_symbol == 0))
         break;
      key = getKey();
      password = password + alphabet[key];
      count_alphabet++;
      count++;
         break;

   case 2:            
      if ((count_ALPHABET == 7) && (count_number == 0 || count_alphabet == 0 || count_alphabet == 5 || count_s_symbol == 0))
            break;
         key = getKey();
         password = password + ALPHABET[key];
         count_ALPHABET++;
         count++;
            break;
   case 3:
      if ((count_number == 7) && (count_alphabet == 0 || count_alphabet == 1 || count_ALPHABET == 3 || count_ALPHABET == 0 || count_s_symbol == 0))
            break;
         key = getKey();           
         key = key % 10;          
         password = password + number[key];
         count_number++;
         count++;
            break;

   case 4:
      if ((count_s_symbol == 1) && (count_alphabet == 0 || count_alphabet == 1 || count_ALPHABET == 0 || count_ALPHABET == 1 || count_number == 0))
            break;
         key = getKey();
         key = key % 6;
         password = password + s_symbol[key];

         count_s_symbol++;
         count++;
            break;
   }
   cout << "\n-----------------------------\n";
   cout << "        Enter The Password             \n";
   cout << "------------------------------\n\n";
   cout << " " << password add here;
   cout << "\n\n Press any key continue \n";
   getchar();
}

在这个语法中，条件检查了一个理想密码的最低要求。我们将每个可能的条件分为四种情况，检查是否满足了字母、数字和特殊符号字符的要求，以及是否满足了最低要求。在处理过程中，如果还有其他字符剩下，那么它将会被忽略。

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方法 - 创建一个强密码建议者

• 方法 1 - 创建强密码建议环境

• 方法 2 - 检查密码是强、弱还是中等

• 方法三 - 检查密码是否符合条件

创建一个强密码建议环境

在此 C++ 构建代码中，系统将检查输入数据（密码）的强度。它将扫描输入以查找理想密码的所有提到的标准。如果所有条件都匹配，那么它就是一个理想的密码。否则，输入中缺少任何字符，它将返回一些随机生成的密码。

Example 1

示例 1

#include 
using namespace std;
string add_more_char(string str, int need){
   int pos = 0;
   string low_case = "abcdefghijklmno";
   for (int a = 0; a < need; a++) {
      pos = rand() % str.length();
      str.insert(pos, 1, low_case[rand() % 26]);
   }
   return str;
}
string suggester(int m, int o, int a, int d, string str) {
   string num = "0123456789";
   string low_case = "abcdefghijklmno";
   string up_case = "ABCDEFGHIJKLMNO";
   string spl_char = "@#$_()!*&%#+-=.`";
   int pos = 0;
   if (m == 0) {
      pos = rand() % str.length();
      str.insert(pos, 1, low_case[rand() % 26]);
   }
   if (o == 0) {
      pos = rand() % str.length();
      str.insert(pos, 1, up_case[rand() % 26]);
   }
   if (a == 0) {
      pos = rand() % str.length();
      str.insert(pos, 1, num[rand() % 10]);
   }
   if (d == 0) {
      pos = rand() % str.length();
      str.insert(pos, 1, spl_char[rand() % 7]);
   }
   return str;
}
void generate_password(int n, string p){
   int l = 0, u = 0, d = 0, s = 0, need = 0;
   string suggest;
   for (int j = 0; j < n; j++) {
      if (p[j] >= 97 && p[j] <= 122)
         l = 1;
      else if (p[j] >= 65 && p[j] <= 90)
         u = 1;
      else if (p[j] >= 48 && p[j] <= 57)
         d = 1;
      else
         s = 1;
   }
   if ((l + u + d + s) == 4) {
      cout << "Hurra! Your Passcode Is Strong, Go Ahead!" << endl;
      return;
   }
   else
   cout << "Suggested password As Per The Input. Pick One For You! " << endl;
   for (int i = 0; i < 10; i++) {
      suggest = suggester(l, u, d, s, p);
      need = 8 - suggest.length();
      if (need > 0)
         suggest = add_more_char(suggest, need);
      cout << suggest << endl;
   }
}
int main(){
   string input_string = "abonirudra@1607";
   srand(time(NULL));
   generate_password(input_string.length(), input_string);
   return 0;
}

输出

Suggested password As Per The Input. Pick One For You! 
abonirudGra@1607
abConirudra@1607
abonirudra@1E607
abonirudra@16A07
abonirudra@160L7
abNonirudra@1607
aNbonirudra@1607
abonirDudra@1607
aboniruFdra@1607
abonirNudra@1607

检查密码强度是否强、弱或中等

根据上述算法和C++构建代码；编码字符串检查输入强度。当满足所有条件时，整个方法返回“Strong”作为输出。如果仅满足前三个步骤并且密码长度至少为八个字符，则它将返回“中等”。

Example 2

示例2

#include 
using namespace std;
void printStrongNess(string& input) {
   int n = input.length();
   bool hasLower = false, hasUpper = false;
   bool hasDigit = false, specialChar = false;
   string normalChars = "abcdefghijklmnopqrstu"
   "vwxyzABCDEFGHIJKL023456789 ";
   for (int i = 0; i < n; i++) {
      if (islower(input[i]))
         hasLower = true;
      if (isupper(input[i]))
         hasUpper = true;
      if (isdigit(input[i]))
         hasDigit = true;
      size_t special = input.find_first_not_of(normalChars);
      if (special != string::npos)
         specialChar = true;
   }
   cout << "Strength of password:-";
   if (hasLower && hasUpper && hasDigit &&
       specialChar && (n >= 8))
   cout << "Strong" << endl;
      else if ((hasLower || hasUpper) &&
   specialChar && (n >= 6))
       cout << "Moderate" << endl;
   else
      cout << "Weak" << endl;
}
int main(){
   string input = "Abonirudra@22052023";
   printStrongNess(input);
   return 0;
}

输出

Strength of password:-Strong

根据条件检查您的密码

在这段代码中，我们将对特定密码进行验证操作。以下是具体的步骤 -

• 接受用户的输入。

• 现在将检查用户输入的密码组合。

• 密码分为强、中、弱三种。

• 如果所有条件都为真，则它将是一个强密码。

• 其他情况下，中等或弱。

Example 3

示例 3

#include 
using namespace std;
void checkpassword(string& password) {
   int n = password.length();
   bool hasLower = false, hasUpper = false, hasDigit = false;
   for (int i = 0; i < n; i++) {
      if (islower(password[i]))
         hasLower = true;
      if (isupper(password[i]))
         hasUpper = true;
      if (isdigit(password[i]))
          hasDigit = true;
   }
   cout << "Strength of password you have entered as per the input :-";
   if ( hasUpper && hasDigit && hasLower && (n >= 6))
      cout << "Strong" << endl;
   else if ((hasLower || hasUpper) && hasDigit && (n >=6))
      cout << "Moderate" << endl;
   else
      cout << "Weak" << endl;
}
int main() {
   cout << "Welcome To The Password Tester! Let's Check Your Password. " << endl;
   cout << "Let's consider the average length of an ideal strong password should be more than 6 character " << endl;
   cout << "Please enter your desired password with :- " << endl;
   cout << " * at least one upper case letter and lower case letter " << endl;
   cout << " * and also need to have at least one digit " << endl; string password;
   cout <<"Enter your monermoto password"<
输出
Welcome To The Password Tester! Let's Check Your Password. 
Let's consider the average length of an ideal strong password should be more than 6 character 
Please enter your desired password with :- 
 * at least one upper case letter and lower case letter 
 * and also need to have at least one digit 
Enter your monermoto password
Strength of password you have entered as per the input :-Weak

结论
从本文中，我们了解了如何使用 C++ 创建密码建议器环境，然后在该特定平台上如何使用一些标签（强、中等、弱）评估密码质量。