输入N，它等于要打印的系列的最大数
Input : N=5 Output : 0 ¼ ½ ¾ 1
算法
START Step 1 -> declare start variables as int num , den, i, n Step 2 -> input number in n Step 3 -> Loop For from i to 0 and iEnd For Loop STOP
示例
#includeint main(int argc, char const *argv[]) { int num, den; int i, n; printf("Enter series limit "); scanf("%d", &n); //Till where the series will be starting from zero for (i = 0; i < n; i++) { if (i%2==0) { //Checking the numerator is odd or even if(i%4==0) { //If the numerator divisible by 4 divide it num = i/4; den = 0; } else {//if not divisible by 4 its even number divisible by 2 num = i/2; den = 2; } } else { //Assigning numerator and denominator value if the number is odd num = i; den = 4; } if (den != 0) { //if denominator is not zero then print in fraaction form printf("%d/%d
",num, den); } else //else print in a normal number form printf("%d
", num); } return 0; }
输出
如果我们运行上述程序，它将生成以下输出
Enter series limit 5 0 1/4 1/2 3/4 1
