phpjavajsonandroid
我通过PHP给android中的java类(Login screen)传递值，但是给出错误JSONException Error，不能从下面的代码中定义。请问如何修改呢？谢谢！
LoginActivity.java
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@Overridepublic void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.login); // Importing all assets like buttons, text fields inputUid = (EditText) findViewById(R.id.loginUid); inputPassword = (EditText) findViewById(R.id.loginPassword); btnLogin = (Button) findViewById(R.id.btnLogin); btnLinkToRegister = (Button) findViewById(R.id.btnLinkToRegisterScreen); loginErrorMsg = (TextView) findViewById(R.id.login_error); // Login button Click Event btnLogin.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { String id = inputUid.getText().toString(); String pswd = inputPassword.getText().toString(); UserFunctions userFunction = new UserFunctions(); Log.d("Button", "Login"); JSONObject json = userFunction.loginUser(id, pswd); // check for login response try { if (json.getString(KEY_SUCCESS) != null) { loginErrorMsg.setText(""); String res = json.getString(KEY_SUCCESS); if(Integer.parseInt(res) == 1){ // user successfully logged in // Store user details in SQLite Database DatabaseHandler db = new DatabaseHandler(getApplicationContext()); JSONObject json_user = json.getJSONObject("user"); // Clear all previous data in database userFunction.logoutUser(getApplicationContext()); db.addUser(json.getString(KEY_ID), json_user.getString(KEY_NAME), json_user.getString(KEY_EMAIL), json_user.getString(KEY_CREATED_AT)); // Launch Dashboard Screen Intent dashboard = new Intent(getApplicationContext(), DashboardActivity.class); // Close all views before launching Dashboard dashboard.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); startActivity(dashboard); // Close Login Screen finish(); }else{ // Error in login loginErrorMsg.setText("Incorrect username/password"); } } } catch (JSONException e) { e.printStackTrace(); } } }); 
