$.ajax({
            url: '/ajax.php',
            type: 'POST',
            contentType: 'application/json; charset=UTF-8',
            crossDomain: true,
            dataType: 'json',
            data: JSON.stringify(data),
            success: function(response) {
            
                alert(response);
                console.log(response);

                $("#spinny").hide();

                var data = response.hits.hits;
                console.log(data);
                var source = null;

                if (data.length > 0) {
                    $("#resultsHeader").html(data.length + " Results").show();
                    for (var i = 0; i < data.length; i++) {
                        source = data[i].fields;
                    }

                } else {
                  //$("#resultsHeader").html("No Results").show();
                    showErrorMessage("#error-container", "Ooops! No results found! Please try again.","alert-danger", true, 3000);
                }

            },
            error: function(jqXHR, textStatus, errorThrown) {
                var jso = jQuery.parseJSON(jqXHR.responseText);
                error_note('section', 'error', '(' + jqXHR.status + ') ' + errorThrown + ' --
' + jso.error);
            }
            

以上的js的提交过程。

以下是ajax.php的代码

hits->total>0) {
        foreach ($arr->hits->hits as $es) {
            $source = $es->_source;
            foreach ($source as $key => $value) {
                echo "$key".":"."$value";
            }
        }
    }
    ?>
                
                

问题:js可以正常生成请求到php，但是取不到php的返回值，不管是 $result还是$key,请问这个怎么回事？
看js的报错，会得到如下的一个提示

"VM2900:1 Uncaught SyntaxError: Unexpected token y in JSON at position 1"