这篇文章主要介绍了python实现获取前100组勾股数的方法,涉及python数值计算与判断相关操作技巧,需要的朋友可以参考下
本文实例讲述了Python实现获取前100组勾股数的方法。分享给大家供大家参考，具体如下：
本来想采用穷举试探的方式来做这个算法，后来发现还是有点麻烦。从网络上找来了一种求解方法如下：
当a为大于1的奇数2n+1时，b=2n^2+2n,c=2n^2+2n+1。实际上就是把a的平方数拆成两个连续自然数。
编写代码如下：
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#!/usr/bin/python
for n in range(1,101):
a = 2 * n +1
b = 2 * (n** 2) + 2 * n
c = b + 1
# check theresult
if a ** 2 +b ** 2 == c ** 2:
print("a= %d, b = %d, c = %d" %(a,b,c))
程序执行结果：
a = 3, b = 4, c = 5a = 5, b = 12, c = 13a = 7, b = 24, c = 25a = 9, b = 40, c = 41a = 11, b = 60, c = 61a = 13, b = 84, c = 85a = 15, b = 112, c = 113a = 17, b = 144, c = 145a = 19, b = 180, c = 181a = 21, b = 220, c = 221a = 23, b = 264, c = 265a = 25, b = 312, c = 313a = 27, b = 364, c = 365a = 29, b = 420, c = 421a = 31, b = 480, c = 481a = 33, b = 544, c = 545a = 35, b = 612, c = 613a = 37, b = 684, c = 685a = 39, b = 760, c = 761a = 41, b = 840, c = 841a = 43, b = 924, c = 925a = 45, b = 1012, c = 1013a = 47, b = 1104, c = 1105a = 49, b = 1200, c = 1201a = 51, b = 1300, c = 1301a = 53, b = 1404, c = 1405a = 55, b = 1512, c = 1513a = 57, b = 1624, c = 1625a = 59, b = 1740, c = 1741a = 61, b = 1860, c = 1861a = 63, b = 1984, c = 1985a = 65, b = 2112, c = 2113a = 67, b = 2244, c = 2245a = 69, b = 2380, c = 2381a = 71, b = 2520, c = 2521a = 73, b = 2664, c = 2665a = 75, b = 2812, c = 2813a = 77, b = 2964, c = 2965a = 79, b = 3120, c = 3121a = 81, b = 3280, c = 3281a = 83, b = 3444, c = 3445a = 85, b = 3612, c = 3613a = 87, b = 3784, c = 3785a = 89, b = 3960, c = 3961a = 91, b = 4140, c = 4141a = 93, b = 4324, c = 4325a = 95, b = 4512, c = 4513a = 97, b = 4704, c = 4705a = 99, b = 4900, c = 4901a = 101, b = 5100, c = 5101a = 103, b = 5304, c = 5305a = 105, b = 5512, c = 5513a = 107, b = 5724, c = 5725a = 109, b = 5940, c = 5941a = 111, b = 6160, c = 6161a = 113, b = 6384, c = 6385a = 115, b = 6612, c = 6613a = 117, b = 6844, c = 6845a = 119, b = 7080, c = 7081a = 121, b = 7320, c = 7321a = 123, b = 7564, c = 7565a = 125, b = 7812, c = 7813a = 127, b = 8064, c = 8065a = 129, b = 8320, c = 8321a = 131, b = 8580, c = 8581a = 133, b = 8844, c = 8845a = 135, b = 9112, c = 9113a = 137, b = 9384, c = 9385a = 139, b = 9660, c = 9661a = 141, b = 9940, c = 9941a = 143, b = 10224, c = 10225a = 145, b = 10512, c = 10513a = 147, b = 10804, c = 10805a = 149, b = 11100, c = 11101a = 151, b = 11400, c = 11401a = 153, b = 11704, c = 11705a = 155, b = 12012, c = 12013a = 157, b = 12324, c = 12325a = 159, b = 12640, c = 12641a = 161, b = 12960, c = 12961a = 163, b = 13284, c = 13285a = 165, b = 13612, c = 13613a = 167, b = 13944, c = 13945a = 169, b = 14280, c = 14281a = 171, b = 14620, c = 14621a = 173, b = 14964, c = 14965a = 175, b = 15312, c = 15313a = 177, b = 15664, c = 15665a = 179, b = 16020, c = 16021a = 181, b = 16380, c = 16381a = 183, b = 16744, c = 16745a = 185, b = 17112, c = 17113a = 187, b = 17484, c = 17485a = 189, b = 17860, c = 17861a = 191, b = 18240, c = 18241a = 193, b = 18624, c = 18625a = 195, b = 19012, c = 19013a = 197, b = 19404, c = 19405a = 199, b = 19800, c = 19801a = 201, b = 20200, c = 20201
由于程序中加入了是否为勾股数的判断，因此这个清单应该是准确的。这个小题目求解下来，我自己的感觉是做事的方法中算法还是至关重要的！
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