数组处理，计算ng数量
本帖最后由 lazygc520 于 2015-05-12 22:26:04 编辑
已知数组a的形式，如果把7020开头的文件看作一个文件，求得这样的结果:ts407,bed410-500a1,5306,ng对应数量为1.这要怎么求？
------解决思路----------------------
<br>array(6) {<br> [0]=><br> string(62) "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020.csv"<br> [1]=><br> string(64) "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_1.csv"<br> [2]=><br> string(64) "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_2.csv"<br> [3]=><br> string(64) "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_3.csv"<br> [4]=><br> string(64) "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_4.csv"<br> [5]=><br> string(65) "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_NG.csv"<br>}<br>已知数组a的形式，如果把7020开头的文件看作一个文件，求得这样的结果:ts407,bed410-500a1,5306,ng对应数量为1.这要怎么求？
------解决思路----------------------
<br>$arr=array(<br> "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020.csv",<br> "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_1.csv",<br> "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_2.csv",<br> "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_3.csv",<br> "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_4.csv",<br> "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7020_NG.csv",<br> "../../dat/DIG/TestFunction/TS407/BED410-500A1/5306/NG/7021_NG.csv",//添加测试<br>);<br>foreach($arr as $v){<br> $tmp=explode('/',$v);<br> $lastfile=array_pop($tmp);<br> preg_match('/^(\d+)(\.<br><font color="#FF8000">------解决思路----------------------</font><br>\_)/',$lastfile,$m);<br> $arr_file[]=$m[1];<br>}<br>$count=count(array_unique($arr_file));<br>echo $count;//2<br>
