问题
在不使用 switch case 的情况下，如何使用 C 编程语言以文字形式打印给定的数字？
解决方案
在此程序中，我们检查三个条件以用单词打印两位数 -
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if(no99)
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if(no99) p>
输入的数字不是两位数
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else if(no==0)
将第一个数字打印为零
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else if(no>=10 && no
用文字打印个位数
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else if(no>=20 && no
if(no%10 == 0)
用文字打印两位数
程序
现场演示
#include
#include int main(){ int no; char *firstno[]={"zero","ten","eleven","twelve","thirteen", "fourteen","fifteen","sixteen","seventeen", "eighteen","nineteen"}; char *secondno[]={"twenty","thirty","forty","fifty","sixty", "seventy","eighty","ninty"}; char *thirdno[]={"one","two","three","four","five","six","seven","eight","nine"}; printf("enter a number:"); scanf("%d",&no); if(no<0 || no>99) printf("enter number is not a two digit number "); else if(no==0) printf("the enter no is:%s
",firstno[no]); else if(no>=10 && no<=19) printf("the enter no is:%s
",firstno[no-10+1]); else if(no>=20 && no<=90) if(no%10 == 0) printf("the enter no is:%s
",secondno[no/10 - 2]); else printf("the enter no is:%s %s
",secondno[no/10-2],thirdno[no%10-1]); return 0; }
输出
enter a number:79 the enter no is: seventy nine enter a number:234 enter number is not a two digit number
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